12t^2-59t+72=0

Solution for 12t^2-59t+72=0 equation:

12t^2-59t+72=0

a = 12; b = -59; c = +72;
Δ = b2-4ac
Δ = -592-4·12·72
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-5}{2*12}=\frac{54}{24}
=2+1/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+5}{2*12}=\frac{64}{24}
=2+2/3
$